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1.33x^2-1.66x-1=0
a = 1.33; b = -1.66; c = -1;
Δ = b2-4ac
Δ = -1.662-4·1.33·(-1)
Δ = 8.0756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.66)-\sqrt{8.0756}}{2*1.33}=\frac{1.66-\sqrt{8.0756}}{2.66} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.66)+\sqrt{8.0756}}{2*1.33}=\frac{1.66+\sqrt{8.0756}}{2.66} $
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